Answer
$$\frac{4x^{2}}{5}$$
Work Step by Step
First, find and divide out any common factors:
$$\frac{7x}{8}\times \frac{32x}{35}=\bigg(\frac{7\times x}{8}\bigg)\times \bigg(\frac{8\times 4\times x}{7\times 5}\bigg).$$
In this case, cancel the factors $7$ and $8$, and the result is
$$\bigg(\frac{x}{1}\bigg)\times \bigg(\frac{4\times x}{5}\bigg)=\frac{4x^{2}}{5}.$$
