Answer
$$\frac{4c}{5}$$
Work Step by Step
Factor the numerator and the denominator and cancel common terms:
$$\frac{28c^{2}(d-3)}{35c(d-3)}=\frac{4\times 7\times c\times c\times(d-3)}{5\times 7\times c\times (d-3)}=\frac{4c}{5}.$$
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