Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - Cumulative Standards Review - Multiple Choice - Page 430: 18

Answer

$1$

Work Step by Step

Factor the radicands so that we can take the cube roots of the numerator and the square roots of the denominator later: $=\dfrac {\sqrt[3] {2^3 \cdot x^{3} \cdot x^{3} \cdot y^{3} \cdot y^{3} \cdot y^{3} \cdot y^{3}}}{\sqrt {2^{2} \cdot x^{2} \cdot x^{2} \cdot y^{2} \cdot y^{2} \cdot y^{2} \cdot y^{2}}}$ Take the cube roots of the numerator and the square roots of the denominator: $=\dfrac {2 \cdot x \cdot x \cdot y \cdot y \cdot y \cdot y }{2 \cdot x \cdot x \cdot y \cdot y \cdot y \cdot y}$ Simplify by canceling similar factors in the numerator and denominator: $=\dfrac{1}{1}$ Simplify: $=1$
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