Answer
$h(x) \times g(x) = -14$
Work Step by Step
In this problem, we are asked to multiply two functions together when given a value for $x$. Let's plug in this value into $h(x)$ first:
$h(1) = 1^2 + 6$
Evaluate exponents first:
$h(1) = 1 + 6$
Add to solve:
$h(1) = 7$
Let's plug in the same value for $g(x)$:
$g(1) = 1 - 3$
Subtract to solve:
$g(1) = -2$
Now, we plug in the two values:
$h(x) + g(x) = (7)(-2)$
We multiply to solve:
$h(x) \times g(x) = -14$
