Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-1 Roots and Radical Expressions - Practice and Problem-Solving Exercises: 66

Answer

$\dfrac{ac}{3}$

Work Step by Step

Factor the denominator, then cancel the common factors: $\require{cancel} =\dfrac{3abc}{3\cdot 3b} \\=\dfrac{\cancel{3}a\cancel{b}c}{3\cdot \cancel{3b}} \\=\dfrac{ac}{3}.$
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