Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 6 - Radical Functions and Rational Exponents - 6-1 Roots and Radical Expressions - Practice and Problem-Solving Exercises: 67

Answer

$\dfrac{4}{x^2}$

Work Step by Step

Factor the numerator and the denominator, then cancel the common factors: $\require{cancel} =\dfrac{4(5x)}{5x(x^2)} =\dfrac{4\cancel{(5x)}}{\cancel{5x}(x^2)} \\=\dfrac{4}{x^2}.$
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