Answer
The solutions are $-\frac{5}{2}$ and $\frac{5}{2}$.
Work Step by Step
Write each term of the binomial in square form to get
$(2x)^2-5^2=0$.
Factor the difference of two squares to get
$(2x-5)(2x+5)=0.$
Equate each factor to 0, then solve each equation for x:
$2x-5=0 \text{ or } 2x+5=0
\\x=\frac{5}{2} \text{ or } x=-\frac{5}{2}.$
Thus, the solutions are $-\frac{5}{2}$ and $\frac{5}{2}$.
