Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 5 - Polynomials and Polynomial Functions - 5-2 Polynomials, Linear Factors, and Zeros - Practice and Problem-Solving Exercises - Page 295: 68

Answer

The solution set is $\left\{\frac{1}{2}, 3\right\}$.

Work Step by Step

Factor the trinomial to get $\\(2x-1)(x-3)=0$. Equate each factor to 0, then solve each equation for x: $2x-1=0 \text{ or } x-3=0 \\x=\frac{1}{2} \text{ or } x=3.$ Thus, the solutions are $\frac{1}{2}$ and 3.
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