Algebra 2 Common Core

Published by Prentice Hall
ISBN 10: 0133186024
ISBN 13: 978-0-13318-602-4

Chapter 3 - Linear Systems - 3-2 Solving Systems Algebraically - Practice and Problem-Solving Exercises: 32

Answer

Infinite solutions (all points along the line $d = 3a - 1$)

Work Step by Step

Given: $9a - 3d = 3$ $-3a + d = -1$ Multiply the second equation by $3$: $-9a + 3d = -3$ Add equations: $9a - 3d + (-9a + 3d) = 3 + (-3)$ Expand: $9a - 9a - 3d + 3d = 3 - 3$ Simplify: $0 = 0$ Therefore infinite solutions. Solve to make $d$ the subject: Second: $-3a + d = -1$ Add $3a$: $d = 3a - 1$ Therefore infinite solutions, all points along the line $d = 3a - 1$
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