Answer
No solutions.
Work Step by Step
Given:
$3x + 2y = 10$
$6x + 4y = 15$
Multiply the first equation, $3x + 2y = 10$, by $2$.
$6x + 4y = 20$
Subtract the first equation, $6x + 4y = 20$, from the second equation, $6x + 4y = 15$.
$6x + 4x - (6x + 4x) = 15 - (20)
\\6x+4x-(6x+4x)=-5$
Subtract each term of the binomial:
$6x - 6x + 4x - 4x = -5$
Combine like terms:
$0 = -5$
This is a contradiction, as obviously $0 \ne -5$.
Thus, there are no solutions.