Answer
a) 4242 committees with at least 1 woman
b) 4221 committees with at least 1 man and 1 woman
Work Step by Step
a) Total people = 9 + 7 = 16
Total committees of 5 members possible = $C$(16,5) = 4368
Committees with only men = $C$(9,5) = 126
Committees with at least 1 woman = Total - only men = 4368 - 126 = 4242
b) committees with only women = $C$(7,5) = 21
Committees with at least 1 man and 1 woman = total - only men - only women = 4368 - 126 - 21 = 4221