Answer
609,638,400 ways to them to stand in a line when no two women are adjacent.
Work Step by Step
First let us make all the men stand in a line. The ways in which this could be done = 8!
Then we let women stand in places where there is always a man between them. We have 9 places where women can go. So the arrangement is given by $C$(9,5), as we have 9 spots and 5 women.
Women can interchange their position in 5! ways
So total arrangements are given by 8!$\times$$C$(9,5)$\times$5! = 609,638,400
