University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 33 - The Nature and Propagation of Light - Problems - Exercises - Page 1110: 33.63

Answer

Choice D.

Work Step by Step

Light reflected from a glass surface is totally polarized, parallel to the surface, when the incident angle equals Brewster’s angle. Assume n = 1.5 for glass. Equation 33.8 tells us $tan \theta_p=\frac{n_b}{n_a}$. $$tan \theta_p=\frac{1.5}{1.00}$$ $$\theta_p=56.3^{\circ}$$ The angle is measured relative to the normal to the surface, i.e., in this case it is measured off the vertical. Figure 33.27 shows that the plane of the electric field vector, after light reflects from the glass, is horizontal. So the light is horizontally polarized when it comes in at an angle of $90^{\circ}-56.3^{\circ}=33.7^{\circ}$ above the glass. Putting all these facts together, we see that the H cells will respond much more strongly to light coming in at an angle of $35^{\circ}$ above the glass than the V cells do.
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