University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 33 - The Nature and Propagation of Light - Problems - Exercises - Page 1107: 33.41

Answer

1.28

Work Step by Step

By using Snell's law, $n_{a} sin \theta_{a}= n_{b} sin \theta_{b}$ where $n_{a}$= refractive index of glass=1.52 $\theta_{a}$= angle of incidence= 57.2$^{\circ}$ $\theta_{b}$= angle of refraction= 90$^{\circ}$ ( since ray is totally reflected) Let $n_{b}$= $n_{oil}$ = 1.52$\times$ sin(57.2)= $n_{oil}$$\times$ sin(90) =$n_{oil}$= $\frac{1.52sin(57.2)}{1}$= 1.28
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