Answer
Choice B.
Work Step by Step
The current in the circuit is $i=i_0e^{-Rt/L}$.
Solve for the time $t_{0.5}$ for the current to reach one-half of its original value.
$$i=i_0e^{-Rt/L}$$
$$0.5i_0=i_0e^{-R t_{0.5}/L}$$
$$ t_{0.5}=(L/R)ln2=\frac{4.4H}{0.005\Omega}ln2=610s$$
That’s about 10 minutes.