University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 23 - Electric Potential - Problems - Exercises - Page 777: 23.2

Answer

$U_ b = 7.3 \times 10^{-8} \,\text{J} $

Work Step by Step

The work done is the difference between the two potential energies at the different points and we could get the potential energy at point $b$ by using this concept by \begin{gather*} W = U_a - U_b \\ U_b = U_a - W\\ U_b = + 5.4 \times 10^{-8} \,\text{J} - (- 1.9 \times 10^{-8} \,\text{J} )\\ \boxed{U_b = 7.3 \times 10^{-8} \,\text{J} } \end{gather*}
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