University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 15 - Mechanical Waves - Problems - Exercises - Page 498: 15.15

Answer

(a) $v = 17.5~m/s$ (b) $\lambda = 0.146~m$ (c) $v = 24.7~m/s$ $\lambda = 0.206~m$

Work Step by Step

(a) We can find the speed of a transverse wave. $v= \sqrt{\frac{F_T}{\mu}}$ $v= \sqrt{\frac{mg}{\mu}}$ $v= \sqrt{\frac{(1.50~kg)(9.80~m/s^2)}{0.0480~kg/m}}$ $v = 17.5~m/s$ (b) We can find the wavelength. $\lambda = \frac{v}{f}$ $\lambda = \frac{17.5~m/s}{120~Hz}$ $\lambda = 0.146~m$ (c) We can find the speed of a transverse wave. $v= \sqrt{\frac{F_T}{\mu}}$ $v= \sqrt{\frac{mg}{\mu}}$ $v= \sqrt{\frac{(3.00~kg)(9.80~m/s^2)}{0.0480~kg/m}}$ $v = 24.7~m/s$ We can find the wavelength. $\lambda = \frac{v}{f}$ $\lambda = \frac{24.7~m/s}{120~Hz}$ $\lambda = 0.206~m$ Note that the speed and the wavelength increased by a factor of $\sqrt{2}$ after the mass increased by a factor of 2.
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