University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 15 - Mechanical Waves - Problems - Discussion Questions - Page 496: Q15.2

Answer

$\frac{F}{9}$.

Work Step by Step

The speed of a wave on a string, as shown in equation 15.14, depends on the tension and linear mass density. $$v=\sqrt{\frac{F}{\mu}}$$ For the pulse to take 3 times as long to travel the length of the wire means that the speed has been reduced by a factor of 3. This happens when the tension F is reduced by a factor of 9.
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