Answer
$2.7Kg.\frac{m}{s}$
Work Step by Step
We know that
$I=\Delta p_y=m\Delta v_y$
$\implies I=m[v_{\circ}65^{\circ}-(-v_{\circ}cos65^{\circ})] $
We plug in the known values to obtain:
$I=(0.60)(5.4)(2cos65^{\circ})$
$I=2.7Kg.\frac{m}{s}$