Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 215: 90

Answer

(a) $930N/m$ (b) $1.7cm$

Work Step by Step

(a) We can find the required spring constant as follows: $K=\frac{mv_{\circ}^2}{x^2}$ We plug in the known values to obtain: $K=\frac{(1.4)(0.62)^2}{(0.024)^2}$ $K=930N/m$ (b) We can find the new required maximum compression as follows: $\frac{x_{new}}{x_{old}}=\frac{\sqrt{m_{new}v_{new}^2/K}}{\sqrt{m_{old}v_{old}^2/K}}=\sqrt{\frac{(2m_{old})(\frac{1}{2}v_{old})^2}{m_{old}v_{old}^2}}={\frac{1}{\sqrt 2}}$ This can be rearranged as: $x_{new}=\frac{x_{old}}{\sqrt 2}$ $\implies x_{new}=\frac{2.4cm}{\sqrt 2}=1.7cm$
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