Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 6 - Applications of Newton's Laws - Problems and Conceptual Exercises - Page 185: 92

Answer

(a) $T=0.0063N$ (b) greater

Work Step by Step

(a) We know that $T=\frac{mg}{2sin\theta}$ We plug in the known values to obtain: $T=\frac{(0.16\times 10^{-3})(9.81)}{2sin7.2^{\circ}}$ $T=0.0063N$ (b) Tension and the angle are related as $T=\frac{mg}{2sin\theta}$. This equation shows that tension and angle are inversely proportional. Thus, by decreasing the angle, the tension will increase.
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