Answer
$2.8Kg$
Work Step by Step
We can find the required mass as follows:
$f_s=\mu_sm_Ag=m_Bg$
This simplifies to:
$m_B=\mu_sm_A$
We plug in the known values to obtain:
$m_B=(0.320)(8.82)$
$m_B=2.8Kg$
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