Answer
The initial speed is $v_0=24.8\text{ m/s}$.
Work Step by Step
We know that
$t=\frac{2v_{\circ}sin\theta}{g}$
We plug in the known values to obtain:
$4.5s=\frac{2v_{\circ}(sin 63^{\circ})}{9.8m/s^2}$
This simplifies to:
$v_{\circ}=24.8m/s$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 4 - Two-Dimensional Kinematics - Problems and Conceptual Exercises - Page 106: 39
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