Chapter 3 - Vectors in Physics - Problems and Conceptual Exercises - Page 78: 28

$B_x=-2.87m$ $B_y=2.01m$

We can find the x and y components of the given vector as follows: (Let the vector be represented by the letter B) $B_x=Bcos\theta$ $\implies B_x=(3.50m)cos(145^{\circ})=-2.87m$ Similarly $B_y=Bsin\theta$ $\implies B_y=(3.50m)sin(145^{\circ})=2.01m$