Answer
(a) $\theta=4.8°$
(b) $d=0.34~mi$
Work Step by Step
See conversion factors (inside front cover).
$1~mi=5280~ft$
(a) $1.2~mi=(1.2~mi)(\frac{5280~ft}{1~mi})=6336~ft$
$sen~\theta=\frac{h}{d}$
$\theta=sin^{-1}(\frac{h}{d})=sin^{-1}(\frac{530~ft}{6336~ft})=4.8°$
(b) $d=\frac{h}{sin~\theta}=\frac{150~ft}{sin~4.8°}(\frac{1~mi}{5280~ft})=0.34~mi$
