Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 945: 106

Answer

(a) $-61cm$ (b) upright (c) $0.47m$

Work Step by Step

(a) We kn ow that $d_i=\frac{fd_{\circ}}{d_{\circ}-f}$ We plug in the known values to obtain: $d_i=\frac{(-84cm)(220cm)}{220cm-(-84cm)}=-61cm$ The negative sign indicates that the image is virtual and behind the mirror. (b) As $m=-\frac{d_i}{d_{\circ}}$ $\implies m=\frac{-(-61cm)}{220cm}=0.277$ The positive value shows that the image of the person is upright. (c) As $m=\frac{h_i}{h_{\circ}}$ $\implies h_i=mh_{\circ}$ We plug in the known values to obtain: $h_i=(0.277)(1.7m)=0.47m$
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