Answer
$0.375$
Work Step by Step
We can find the required fraction of incident light as follows:
$I_1=\frac{1}{2}I_{\circ}$
and $I_2=\frac{1}{2}I_{\circ}cos^2\theta$
Now $\frac{I_2}{I_1}=\frac{1}{2}cos^2 30.0^{\circ}=0.375$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 903: 74
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