Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 24 - Alternating-Current Circuits - Problems and Conceptual Exercises - Page 867: 3

Answer

$81\Omega$

Work Step by Step

As we know that $V=\sqrt{2}V_rms$ $\implies V=\sqrt{2}(120)=170V$ Now we can find the required resistance as $R=\frac{V}{I}$ We plug in the known values to obtain: $R=\frac{170}{2.1}=81\Omega$
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