Answer
$(C)\ 2.1\times 10^{-4}V$
Work Step by Step
We know that
$\epsilon=(N)|\frac{(B_2-B_1)\pi r^2}{\Delta t}|$
We plug in the known values to obtain:
$\epsilon=(4)(\frac{(2.6\times 10^{-5}-1.2\times 10^{-5}\pi)(0.67)^2}{0.38})$
$\epsilon=2.1\times 10^{-4}V$