Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 795: 60

Answer

$NC=21Km$

Work Step by Step

We can find the total length of wire as $NC=\frac{B}{\mu_{\circ}I}L(\pi d)$ We plug in the known values to obtain: $NC=\frac{2.5\times 10^3\times 1.0T/10^4G}{4\times 10^{-7}(2.0)}\times (0.55)(0.12)$ $NC=21Km$
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