Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 21 - Electric Current and Direct-Current Circuits - Problems and Conceptual Exercises - Page 762: 124

Answer

$(A)~3.70\times 10^{-6}A$

Work Step by Step

We can find the required current as follows: $I=\frac{V}{R}$ We plug in the known values to obtain: $I=\frac{3.7V}{1\times 10^6\Omega}$ $I=3.70\times 10^{-6}A$
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