Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 21 - Electric Current and Direct-Current Circuits - Problems and Conceptual Exercises - Page 760: 99

Answer

Connect $521\Omega$ and $146\Omega$ in series and then connect this pair in parallel with $413\Omega$.

Work Step by Step

We should connect $521\Omega$ and $146\Omega$ in series and then we should connect $413\Omega$ in parallel to obtain the required equivalent resistance $255\Omega$. This is shown as follows: $R{eq_1}=521+146=667$ Now $R_{eq}=(\frac{1}{667}+\frac{1}{413})^{-1}$ $R_{eq}=255\Omega$
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