Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 721: 78

a) $\Delta V=-9.1KV$ b) $\Delta V=-9.1KV$ c) $\Delta V=9.1KV$

(a) We know that $\Delta V=V_B-V_A=\frac{W}{q_{\circ}}$ We plug in the known values to obtain: $\Delta V=-\frac{0.052}{5.7\times 10^{-6}}$ $\Delta V=-9.1KV$ (b) As $\Delta V=V_B-V_A=\frac{W}{q_{\circ}}$ We plug in the known values to obtain: $\Delta V=-\frac{-0.052}{-5.7\times 10^{-6}}$ $\Delta V=-9.1KV$ (c) $\Delta V=V_B-V_A=\frac{W}{q_{\circ}}$ We plug in the known values to obtain: $\Delta V=\frac{0.052}{5.7\times 10^{-6}}$ $\Delta V=9.1KV$