Answer
(a) $A=0.060~m^{2}$
(b) $A_{2}=\frac{1}{4}A_{1}$
Work Step by Step
(a) $1~in=2.54\times10^{-2}~m$
$A=L\times W=(8.5~in)(11~in)=93.5~in^{2}$
$A=(93.5~in^{2})(\frac{2.54\times10^{-2}~m}{1~in})^{2}=0.060~m^{2}$
(b) $A_{1}=L_{1}\times W_{1}$ and $A_{2}=L_{2}\times W_{2}$
$L_{2}=\frac{L_{1}}{2}$ and $W_{2}=\frac{W_{1}}{2}$. So:
$A_{2}=L_{2}\times W_{2}=\frac{L_{1}}{2}\times \frac{W_{1}}{2}=\frac{1}{4}(L_{1}\times W_{1})=\frac{1}{4}A_{1}$
