Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - Problems - Page 166: 51

Answer

The average coefficient of friction was 0.091.

Work Step by Step

The potential energy at the highest point on the slope is equal to the original kinetic energy plus the work done by friction. Therefore, $KE + Work = PE$ $Work = PE - KE$ $F_f~d\times cos(180) = mgh -\frac{1}{2}mv^2$ $-mg\mu ~d = mgh -\frac{1}{2}mv^2$ $-\mu = \frac{gh -\frac{1}{2}v^2}{gd}$ $-\mu = \frac{(9.8 ~m/s^2)(15 ~m\times sin(19)) -\frac{1}{2}(11.0 ~m/s)^2}{(9.8 ~m/s^2)(cos(19))(15 ~m)}$ $\mu = 0.091$ The average coefficient of friction was 0.091.
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