Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - Problems - Page 135: 57

Answer

The length of the Neptunian year is 160 Earth years.

Work Step by Step

$(\frac{T_{N}}{T_{E}})^2 = (\frac{s_N}{s_E})^3$ $(\frac{T_{N}}{T_{E}}) = (\frac{s_N}{s_E})^{3/2}$ $(\frac{T_{N}}{T_{E}}) = (\frac{4.5 \times 10^9 ~km}{1.5\times 10^8 ~km} )^{3/2}$ $(\frac{T_{N}}{T_{E}}) = (30)^{3/2}$ $(\frac{T_{N}}{T_{E}}) = 164$ $T_N = 164\times T_E = 164\approx160 ~years$ The length of the Neptunian year is 160 Earth years.
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