Answer
6 $\frac{nucleons}{m^3}$
Work Step by Step
Choose a proton as a typical nucleon.
$$(10^{-26}\frac{kg}{m^3})(\frac{nucleon}{1.67\times10^{-27}kg})$$
$$=6\frac{nucleons}{m^3}$$
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 33 - Astrophysics and Cosmology - Problems - Page 982: 35
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