Answer
$1.1\times10^{-7}F$
Work Step by Step
If the current and voltage are in phase, the net reactance of the capacitor and inductor is zero. In other words, the circuit is at resonance. Equation 21-19 gives the resonant frequency.
$$f_o=\frac{1}{2 \pi}\sqrt{\frac{1}{LC}}$$
$$C=\frac{1}{4\pi^2Lf_o^2}$$
$$C=\frac{1}{4\pi^2(0.130H)(1360Hz)^2}=1.1\times10^{-7}F$$