Answer
$v_x = 3.7~m/s$
$v_y = -2.6~m/s$
Work Step by Step
$v_x = v~cos(\theta)$
$v_x = (4.5~m/s)~cos(35^{\circ})$
$v_x = 3.7~m/s$
$v_y = -v~sin(\theta)$
$v_y = -(4.5~m/s)~sin(35^{\circ})$
$v_y = -2.6~m/s$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 3 - Vectors and Coordinates Systems - Exercises and Problems - Page 78: 33
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