## Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson

# Chapter 19 - Work, Heat, and the First Law of Thermodynamics - Exercises and Problems: 3

#### Answer

$V_1 = 200~cm^3$

#### Work Step by Step

We can find $V_1$ as: $W = -P\Delta V$ $W = -P ~(V_f-V_i)$ $W = -P ~(V_1-3V_1)$ $W = 2P ~V_1$ $V_1 = \frac{W}{2P}$ $V_1 = \frac{80~J}{(2)(2.00\times 10^5~Pa)}$ $V_1 = 2.0\times 10^{-4}~m^3$ $V_1 = (2.0\times 10^{-4}~m^3)(\frac{10^6~cm^3}{1~m^3})$ $V_1 = 200~cm^3$

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