Answer
(a) $V = 0.050~m^3$
(b) $P = 1.3\times 10^5~Pa$
Work Step by Step
(a) We can use the ideal gas law to solve this question.
$PV = nRT$
$V = \frac{nRT}{P}$
$V = \frac{(2.0~mol)(8.314~m^3~Pa/mol~K)(303~K)}{1.013\times 10^5~Pa}$
$V = 0.050~m^3$
(b) We can use the ideal gas law to solve this question.
$PV = nRT$
$P = \frac{nRT}{V}$
$P = \frac{(2.0~mol)(8.314~m^3~Pa/mol~K)(403~K)}{0.050~m^3}$
$P = 1.3\times 10^5~Pa$
