Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 6 - Dynamics I: Motion Along a Line - Exercises and Problems: 17

Answer

$\mu_k = 0.25$

Work Step by Step

Since the safe moves with a constant speed, the acceleration is zero. We can set up a force equation to find the coefficient of kinetic friction. Therefore; $\sum F = ma$ $385~N+350~N-F_f = 0$ $mg~\mu_k = 385~N+350~N$ $\mu_k = \frac{735~N}{(300~kg)(9.80~m/s^2)}$ $\mu_k = 0.25$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.