Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 29 - Potential and Field - Exercises and Problems - Page 865: 65

Answer

$V = 850~V$

Work Step by Step

We can find the total energy that was supplied: $U = P~t = (6500~W)(5.0\times 10^{-3}~s) = 32.5~J$ We can find the voltage: $U = \frac{1}{2}CV^2$ $V^2 = \frac{2U}{C}$ $V = \sqrt{\frac{2U}{C}}$ $V = \sqrt{\frac{(2)(32.5~J)}{90\times 10^{-6}~F}}$ $V = 850~V$
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