Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 23 - Ray Optics - Exercises and Problems - Page 690: 40

Answer

$20^\circ$

Work Step by Step

From the geometry of the figure below, we can see that angle $\phi$ is 20$^\circ$. The main idea here is the two angles of 40$^\circ$ of the two parallel lines that are parallel to the bisector of angle $80^\circ$. And hence, the two 40$^\circ$s angles appear. Also, we know that the angle of the incident ray relative to the normal is equal to the reflected ray angle relative to the same normal as well. Therefore, we got $$\phi=\color{red}{\bf20^\circ}$$
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