Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 2 - Kinematics in One Dimension - Exercises and Problems: 11

Answer

(a) x = 6.0 m (b) v = 4.0 m/s (c) $a = 2.0 ~m/s^2$

Work Step by Step

(a) The area between the velocity versus time graph and the x-axis is equal to the displacement. $\Delta x = 4.0 ~m$ $x = x_0+\Delta x$ $x=2.0~m + 4.0 ~m$ $x=6.0 ~m$ (b) We can read the value of the velocity directly from the graph. The value is: v = 4.0 m/s (c) The acceleration is equal to the slope of the velocity versus time graph. $a = \frac{6.0 ~m/s}{3.0 ~s} = 2.0 ~m/s^2$
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