#### Answer

(a) x = 6.0 m
(b) v = 4.0 m/s
(c) $a = 2.0 ~m/s^2$

#### Work Step by Step

(a) The area between the velocity versus time graph and the x-axis is equal to the displacement.
$\Delta x = 4.0 ~m$
$x = x_0+\Delta x$
$x=2.0~m + 4.0 ~m$
$x=6.0 ~m$
(b) We can read the value of the velocity directly from the graph. The value is:
v = 4.0 m/s
(c) The acceleration is equal to the slope of the velocity versus time graph.
$a = \frac{6.0 ~m/s}{3.0 ~s} = 2.0 ~m/s^2$