Answer
$150J$
Work Step by Step
We can find the required heat as follows:
$Q=nT_1(\frac{V_1-V_2}{V_2})(C_v-R)$
We plug in the known values to obtain:
$Q=(0.02)(293)(\frac{1.5-0.5}{0.5})(20.8-8.31)$
This simplifies to:
$Q=150J$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0321740904
ISBN 13:
978-0-32174-090-8
Chapter 17 - Work, Heat, and the First Law of Thermodynamics - Exercises and Problems - Page 501: 81
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