Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

$V = 50~mL$
We first find the volume in units of $m^3$. $V = \frac{M}{\rho}$ $V = \frac{0.055~kg}{1100~kg/m^3}$ $V = 5.0\times 10^{-5}~m^3$ We then convert the volume to units of mL. $V = (5.0\times 10^{-5}~m^3)(\frac{10^6~mL}{1~m^3})$ $V = 50~mL$