Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 11 - Work - Exercises and Problems - Page 307: 66

Answer

$18\;\rm hp$

Work Step by Step

We know that the power is given by $$P=Fv$$ We know that the power to tow a water skier at a speed of 2.5 mph is about 2 hp. In our case, we know that the tow force is given by $F_{tow}=Av$ $$P_{tow}=(Av)v=Av^2$$ And to find the power to tow the same skier at speed of 7.5 mph, we need to find the proportionality constant $A$. Thus, $$A=\dfrac{P_{tow,1}}{v^2_1}$$ Plugging the known; $$A=\dfrac{2}{2.5^2 }=\bf 0.32\;\rm hp/(mph)^2$$ Now we can easily find the power needed at speed of 7.5 mph. $$P_{tow,2}= Av_2^2$$ Plugging the known; $$P_{tow,2}=0.32\times 7.5^2$$ $$P_{tow,2}=\color{red}{\bf 18}\;\rm hp$$
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