Answer
The phase difference is $~~2~wavelengths$
Work Step by Step
We can find the phase difference in terms of wavelengths:
$\frac{\Delta L}{\lambda} = \frac{38~m-34~m}{2.0~m} = 2~wavelengths$
The phase difference is $~~2~wavelengths$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 17 - Waves-II - Questions - Page 505: 2a
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