College Physics (7th Edition)

Published by Pearson
ISBN 10: 0-32160-183-1
ISBN 13: 978-0-32160-183-4

Chapter 3 - Motion in Two Dimensions - Learning Path Questions and Exercises - Exercises - Page 102: 85

Answer

a). Initial velocity =u=$(16.4x-11.5y) m/s$ Final velocity =v=$(9.06x+4.28y) m/s$ b). Change in velocity =$(-7.34x+15.78y) m/s$ c). Magnitude =$17.33m/s$ The angle = $64.49^{\circ}$ above (-) x axis.

Work Step by Step

a). Initial velocity =u=$20cos35^{\circ}x-20sin35^{\circ}y=(16.4x-11.5y) m/s$ Final velocity =v=$10cos25^{\circ}x+10sin25^{\circ}=(9.06x+4.28y) m/s$ b). Change in velocity =$(9.06x+4.28y)-(16.4x-11.5y)=(-7.34x+15.78y) m/s$ c). Magnitude =$\sqrt ((-7.34)^{2}+15.78^{2})=17.33m/s$ The angle =$tan^{-1}(\frac{15.78}{-7.34})=-64.49^{\circ}$
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